Expert answer:C++ simple coding. see attachment for details.
Answer & Explanation:homework 4.pdf
homework_4.pdf
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Computer Science 120
Homework 4 (3 points)
Due: 2015-10-18
Given:
int main(int argc, char **argv)
{
string words;
short number, hundreds, tens, ones;
hundreds = tens = ones = -1;
number = atoi(argv[1]);
if(number > 999 || number < 0) {
cerr << "Not a positive three-digit number!" << endl;
return 1;
}
if(number == 0) {
cout << "zero" << endl;
return 0;
}
Deliverables:
main.cpp
Requirements:
Write a program that converts a two-digit integer into words.
• First, change the supplied code to apply to two-digit numbers, since this homework was
originally going to be done with three digits.
• Write switch-cases to convert a number into words (45 → fourty-five).
• You may use no more than two if statements. (Or none. There are a few different ways to
do this.)
• NOTICE that you do not have to use cin to get the number from the user. It's taken as an
argument when you call the program, like numconvert.exe 45 . (atoi(argv[1]) is
taking the number (taken as a c-string from the argument array) into an integer.)
Notes:
• Notice that the digit places are -1, which makes comparing easy, since you will only be
using positive numbers anyway.
• What easy math function can separate a number into its separate digits? (Same one that
can be used to distinguish between odds and evens.)
• Remind me to show you how to pass arguments to the executable in CodeLite so that you
don't have to switch to a terminal to do it. You can simply cheat, and make number equal
some number for now.
...
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