Expert answer:StackGeneric and Interfaces Exceptions

Solved by verified expert:Build on the examples given in 1009-classwork.zip.1.Explain why the following code will not compile:import StackGeneric.*;

public class Test0 {

public static void main(String [] args){
Stack st = new Stack();
for( int i = 0 ; i < 5 ; i++) { st.push(i); } st.push(5); System.out.println(st.pop()); } } 2.Explain why the following two examples throw an exception when run.import StackGeneric.*; public class Test { public static void main(String [] args){ Stack st = new IntegerStackArray();
int n = st.pop();
}
}
import StackGeneric.*;

public class Test2 {

public static void main(String [] args){
Stack st = new IntegerStackArray();
for( int i = 0 ; i < 1000 ; i++) { st.push(i); } st.push(5); } } 3.Read the Java tutorial on Exceptions, up to and including the section on finally blocks.4.In Problem 2. above, both examples threw ArrayIndexOutOfBoundsException exceptions. Using the following template, modify the methodpublic void push(Integer value)so that if pushing results in exceeding the maximum size of the array, the ArrayIndexOutOfBoundsException is caught, an appropriate message is printed, but the program continues, though the requested action is not completed.Template:try{ /* … */ }
catch(ArrayIndexOutOfBoundException e){ /* … */ }
5.In the above example, I referred to the method “push” using the full signature. Why is this good practice, rather than just writing “push”?6.Complete the problem described in the picture slide 1(1009 Information) in the folder 10/09.
1009_classwork.zip

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