q1. A regression equation was fit relating a student’s weig
q1. A regression equation was fit relating a student’s weight to… q1. A regression equation was fit relating a student’s weight to the number of hours they spend on the computer (x1), the number of hours they spend watching television (x2), and the number of hours they spent on the telephone (x3). The estimated regression equation isy = 125.5 + 3.26 x 1 + 4.27 x 2 + 1.75 x 3 .What is a student’s predicted weight if the student spends 4 hours on the computer, 2 hours viewing television, and 3 hours on the telephone? a.152.33 b. 153.22 c. 151.83 d. 154.35 e. 155.86ans: q2. A health science-kinesiology program to lose weight collected data from ten students. Sex was coded as 1=female and 0=male. The regression equation obtained by using a statistical software was:Pounds lost = 15.8 + 0.65 time + 6.00 sexThe estimated weight loss of a male who stayed in the program for 5 periods is: a. 19.05 b. 15.8 c. 3.25 d. 25.05 e. 6Answer:q3. In a random sample of 1000 adults in the United States, 500 of them said they could not cover a $400 unexpected expense without borrowing money or going into debt (running into their credit cards). In here, the sample is from all adults in the United States, so US adults is the population under consideration. The fraction of US adults who could not cover a $400 expense without borrowing money or selling something is the population parameter to be estimated. Given the information in the question, what is the point estimate (sample statistics) for the population parameter? a. p =0.5 b. p =500 c. p =0.25 d. p =0.015 ans: Engineering & Technology Computer Science ADTA 5130
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