Question B. Beer’s Law In solutions A-D, essentially all of the Fe?+ reacts… B. Beer’s LawIn solutions A-D, essentially all of the Fe?+reacts to form FeSSA. There are two reasons for this. First, the equilibrium constant for the formation of the product is large. Secondly, adding excess HaSSA® forces the reaction to the right. Therefore, for each of these solutions you can calculate the final (FeSSA]. Plot absorbance (on the y axis) vs concentration of FeSSA (on the x axis.) This MUST be a computer graph with a computer fit, straight line through 0,0! ReportEl with units. Find the slope of the straight line through these data points._______________________C. Determine K, the equilibrium constant.In this experiment, every solution you use contains 0.1M HCIOA. This strong acid is present to prevent chemical reactions that happen in less acidic environments. Because the concentration of the strong acid never changes, the [H*] is constant and can be included in the equilibrium constant. Thus the equilibrium constant we will determine is for the reaction: Fe? (aq) + HaSSA (aq) = FeSSA(aq) + (ignore the 2 H*)Using reaction tables and your data from solutions E-I, determine the equilibrium constant independently for each solution E-I. Each solution will have a slightly different reaction table and calculation. An example will be shown in class. Calculate the average and relative range of the five resulting equilibrium constants. Show ALL of your calculations either in your notebook or on separate sheets, neatly!__________________________D. Discussion/Conclusions.Summarize your results in a table showing theequilibrium constants Kc that you calculated for each solution, as well as the average and relative range. Comment on the precision. Should they all be the same? Why or why not? Discuss why your experimental results may differ from theoretical expections in this respect, ie, give an error analysis. Image transcription textchem+1b+lab+manual+december+2017 Measuring data by 20nm and measuring the absorbances Measuringdata by 5nm once we reach the highest G 40Onm absorbance (lambda theta) to then see if we have another 0.152 A higher absorbance 485 nm 0.502A 4210 mm 0. 206 A 490 am 0. 511 A 440 O. 304 A 495 m… Show more… Show more Science Chemistry CHEM 1B
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