Expert answer:Write a method where the signature is: public stat

Answer & Explanation:In Java.
A.
Write a method where the signature is:
public static int subStrC(String s, char c)
Which receive a string ‘s’ and a char ‘c’ and returns how many sub string has in ‘s’ that ends in the char ‘c’ and they have inside them exactly one time the char ‘c’
for example. for the given string s=”abcbcabcacabcc” and the char c=’c’ the result would be 4
(because the sub strings are “cabcc”,”cacabc”,”cabcac”,”cbcabc”)
No need to return the sub strings. just the number of sub strings.
B.
Write a method where the signature is:
public static int subStrMaxC(String s, char c, int k) 
That gets the string ‘s’, the char ‘c’ and a positive number ‘k’ and returns how many sub strings ‘s’ has that starts and ends in the char ‘c’ and Inside them maximum ‘k’ times the char ‘c’
No need to return the sub strings – just their numbers.
Examples:
1.If the string is: s=”abcbc” and char ‘c’=’c’ and the number k=0 the result is 1. (sub string is “CBC”)
2.If the string is: s=”abcbcabcacab” and char ‘c’=’c’ and number k=3 the result is 6 again (sub strings are “cbcabcac”, “cabcac”, “cbcabc”, “cac”, “cabc”, “cbc” and there is no sub string s that starts with char ‘c’ and ends in the char ‘c’ and has 3 ‘c’ chars).
3.If the strings is s=”abc”, char c=’c’ and number k=2 the result is 0. there is no sub strings that starts and ends in char ‘c’.
The methods needs to be as efficient as possible.
If the method complexity would be higher then required not all points will be given.
When solving those methods we can only use all the methods in the String class and in compare methods (optional) –
public char charAt(int i) – returns the char at the place i for the string it operated onpublic int length() – returns the length of the string.

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