Expert answer:Multiple Choice Questions A sample of 3.00 moles o

Solved by verified expert:A sample of 3.00 moles of liquid water is heated from 10°C to 80°C. Determine q for this sample of water during this process. (The specific heat of water is 4.18 J/g°C.) –878 J – wrong answer 878 J 18.1 kJ – wrong answer –15.8 kJ 15.8 kJ______________________________________________________________________________________________________________________________8.00 grams of CH4 gas are completely combusted in the presence of excess oxygen gas in a bomb calorimeter. The heat capacity of the calorimeter and its contents is 18.2 kJ/°C, and the calorimeter rises in temperature from 25.0°C to 49.5°C. Determine the enthalpy of combustion of CH4 gas in units of kJ/mol.–56 kJ/mol–446 kJ/mol – wrong answer 446 kJ/mol – wrong answer –892 kJ/mol 892 kJ/mol____________________________________________________________________________________________________________________________Gas grills typically use the combustion of propane, C3H8 (g), to heat up the grill. The combustion of propane is shown in the following balanced chemical reaction:C3H8 (g) + 5 O2 (g) –> 3 CO2 (g) + 4 H2O (l)Using the information given below, determine the ∆H° for this reaction.Useful Information:∆H°f (C3H8 (g)) = –104 kJ/mol∆H°f (H2O (l) = –286 kJ/mol∆H°f (CO2 (g) = –393 kJ/mol –575 kJ/mol –2219 kJ/mol – wrong answer 2219 kJ/mol –2427 kJ/mol____________________________________________________________________________________________________________________________Consider the following chemical reaction and associated change in enthalpy:H2 (g) + F2 (g) ––> 2 HF (g) ∆H = –542 kJ/molDetermine ∆H for the following reaction:HF (g) ––> 12 H2 (g) + 12 F2 (g) ∆H = ???–271 kJ/mol 271 kJ/mol –542 kJ/mol – wrong answer 542 kJ/mol –1084 kJ/mol – wrong answer 1084 kJ/mol__________________________________________________________________________________________________________________________ Consider the following data:NO (g) + 1/2 O2 (g) –> NO2 (g) ∆H = –56 kJ/molN2O4 (g) –> 2 NO2 (g) ∆H = 58 kJ/molDetermine the ∆H for the following reaction:2 NO (g) + O2 (g) –> N2O4 (g) ∆H = –170 kJ/mol ∆H = –54 kJ/mol – wrong answer ∆H = 2 kJ/mol ∆H = 54 kJ/mol ∆H = 170 kJ/mol – wrong answer

How it works

1. Paste your instructions in the instructions box. You can also attach an instructions file
2. Select the writer category, deadline, education level and review the instructions 
3. Make a payment for the order to be assignment to a writer
4.  Download the paper after the writer uploads it 

Will the writer plagiarize my essay?

You will get a plagiarism-free paper and you can get an originality report upon request.

Is this service safe?

All the personal information is confidential and we have 100% safe payment methods. We also guarantee good grades