Expert answer:Conclusion for Ac circuit lab report

Solved by verified expert:I’ve already done about 80% of the lab report. I only need three things to be completed in this experiment: 1) Last column in the table. 2) Part c. 3) The conclusion.please check the units and calculation
lab_7_ac.docx

Unformatted Attachment Preview

1
PART 2: Capacitors
Objective:
We verified that the resistance of a resistor is independent of frequencies in
the audio range as the first part of this experiment. In the second part we verified
that the reactance of an inductor increases linearly with increase in frequency. In
this third part we will verify that the reactance of a capacitor decreases non-linearly
with increase in frequency.
Diagram:
Equipment needed:
➢ Resistor 100Ω.
➢ Capacitors 0.1-µF.
➢ DMM, oscilloscope, Signal generator, Audio oscillator, Frequency counter.
Procedure:
✓
✓
✓
✓
✓
Select the components and measure the value of capacitor and resistor.
Resistor -99.24Ω
Capacitors 0.1-µF.
construct the circuit shown in figure 5.3
Connect the oscilloscope across the resistor and set the voltage across the capacitor 4V
measure the voltage magnitude.
✓ ….
✓ Change the value of frequency and then repeat the procedure.
2
Calculations:
a) Calculate Xc from the measured value at each frequency and insert the values in the
table under the heading Xc measured
b) Calculate Xc using the nameplate capacitance value of 0.1 µF at each frequency and
insert in the Xc (calculated)
I(p-p) = VRs(p-p) / Rs (measured)
For 100 Hz = 20 mV / 99.24 Ω = 0.2 mA
For 200 Hz = 50 mV / 99.24 Ω = 0.5 mA
For 300 Hz = 70 mV / 99.24 Ω = 0.7 mA
For 400 Hz = 90 mV / 99.24 Ω = 0.9 mA
For 500 Hz = 114 mV / 99.24 Ω = 1.15 mA
For 800 Hz = 185 mV / 99.24 Ω = 1.86 mA
For 1000 Hz = 235 mV / 99.24 Ω = 2.37 mA
For 2000 Hz = 460 mV / 99.24 Ω = 4.64 mA
Xc(measured)= Vc (p-p) / I(p-p)
For 100 Hz = 4 V / 0.2 mA = 20 Ω
For 200 Hz = 4 V / 0.5 mA = 8.0 Ω
For 300 Hz = 4 V / 0.7 mA = 5.7 Ω
For 400 Hz = 4 V / 0.9 mA = 4.4 Ω
For 500 Hz = 4V / 1.15 mA = 3.5 Ω
For 800 Hz = 4 V / 1.86 mA = 2.2 Ω
For 1000 Hz = 4 V / 2.37 mA = 1.7 Ω
For 2000 Hz = 4 V / 4.64 mA = 0.9 Ω
Xc(Calculated) = 1 / 2πf c
For 100 Hz = 1 / (2 × π ×100 Hz × 0.1 µF) = Ω
For 200 Hz = 1 / (2 × π × 200 Hz × 0.1 µF) = Ω
For 300 Hz = 1 / (2 × π × 300 Hz × 0.1 µF) = Ω
For 400 Hz = 1 / (2 × π × 400 Hz × 0.1 µF) = Ω
For 500 Hz = 1 / (2 × π × 500 Hz × 0.1 µF) = Ω
For 800 Hz = 1 / (2 × π × 800 Hz × 0.1 µF) = Ω
For 1000 Hz = 1 / (2 × π × 1000 Hz × 0.1 µF) = Ω
For 2000 Hz = 1 / (2 × π × 2000 Hz × 0.1 µF) = Ω
Table 5.4
Frequency Vc(p-p)
(Hz)
100 Hz
200 Hz
4V
4V
VRs(p-p)
20 mV
50 mV
Ip-p
Xc(measured)= Vc (p-p) /
I(p-p)
0.2 mA
0.5 mA
20 Ω
8.0 Ω
Xc(Calculated) =
1/ 2πf c
0.02 Ω
Ω
3
300 Hz
400 Hz
500 Hz
800 Hz
1000 Hz
2000 Hz
4V
4V
4V
4V
4V
4V
70 mV
90 mV
114 mV
185 mV
235 mV
460 mV
0.7 mA
0.9 mA
1.15 mA
1.86 mA
2.37 mA
4.64 mA
5.7 Ω
4.4 Ω
3.5 Ω
2.2 Ω
1.7 Ω
0.9 Ω
c) How do the results in the Xc (measured) and Xc (calculated) compare?
Conclusion:
Ω
Ω
Ω
Ω
Ω
Ω
…
Purchase answer to see full
attachment

How it works

1. Paste your instructions in the instructions box. You can also attach an instructions file
2. Select the writer category, deadline, education level and review the instructions 
3. Make a payment for the order to be assignment to a writer
4.  Download the paper after the writer uploads it 

Will the writer plagiarize my essay?

You will get a plagiarism-free paper and you can get an originality report upon request.

Is this service safe?

All the personal information is confidential and we have 100% safe payment methods. We also guarantee good grades